Hillgrove Lab Lockdown: The Final Reaction ChallengeChemists, we’ve got a problem! The Hillgrove Lab reactor has stabilized, but the containment doors are still sealed. To escape, you must use your knowledge of stoichiometry, BCA tables, and limiting reactants to solve a series of chemistry “locks.” Each correct calculation powers the lab back online — and the final challenge requires you to work backward from the product to find exactly how much of each reactant is needed.
Can you balance the equations, restore full efficiency, and lift the doors before time runs out?
Balance each one to generate the override code (the sum of all coefficients in each reaction). Add the coefficients of each balanced equation above separately. Each sum corresponds to the code.
Enter your 3-digit code.
Example: If the sums of each reaction are:
3
9
4
then your code would be 3-9-4 → enter 394
Fill in the missing “Before” amount of H₂.
Reaction:
2H₂ + O₂ → 2H₂O
Step | H₂ (mol) | O₂ (mol) | H₂O (mol) |
|---|---|---|---|
Before | | 3.0 | 0 |
Change | –4x | –2x | +4x |
After | 0 | 1.0 | 4.0 |
Determine the missing “Change” value for N₂.
Reaction:
N₂ + 3H₂ → 2NH₃
Step | N₂ (mol) | H₂ (mol) | NH₃ (mol) |
|---|---|---|---|
Before | 2.0 | 6.0 | 0 |
Change | | –3x | +2x |
After | 1.0 | 0 | 4.0 |
Determine the missing “After” value for Al.
Reaction:
2Al + 3Cl₂ → 2AlCl₃
Step | Al (mol) | Cl₂ (mol) | AlCl₃ (mol) |
|---|---|---|---|
Before | 3.0 | 5.0 | 0 |
Change | –3.0x | –4.5x | +3.0x |
After | | 0.5 | 3.0 |
Reflect: In your own words, explain what this escape taught you about how limiting reactants and yield affect real chemical systems.
In this final calibration, you worked backward to find the exact reactant amounts needed to reach 100% efficiency. Explain how the ratio of reactants and products demonstrates the Law of Conservation of Matter.