2 \left( \frac{1}{4} + \frac{2}{3} \right) =
\frac{22}{24}
\frac{11}{6}
\frac{6}{7}
\frac{6}{14}
\frac{4}{7}
Simplify \frac{(2xy^2)^3}{(x^2 y)^2}
6xy^4
8x^7 y^8
\frac{6y^3}{x}
\frac{8y^3}{x}
\frac{8y^4}{x}
16^{-1/4} \times 4^0 =
-2
\frac{1}{2}
0
-\frac{1}{2}
2
One factor of 3x^2 + 11x - 4 is
3x+1
x-4
3x-1
x-2
3x+4
Factor x^2 + 2x - 8
(x+2)(x-4)
(x+8)(x-1)
(x-8)(x+1)
(x-2)(x+4)
(x-4)(x-2)
If x^2 - 4x + 1 = 0, then x =
2+\sqrt{3}, 2-\sqrt{3}
-2+\sqrt{3}, -2-\sqrt{3}
2+\sqrt{5}, 2-\sqrt{5}
\sqrt{3}, -\sqrt{3}
None of the above.
Solve the following pair of equations for x and y: 2x - y = 5 and 4x + y = 7
x = -2, \, y = 1
x = 2, \, y = -1
x = 1, \, y = -3
x = 6, \, y = -17
x = 2, \, y = 1
If x = 11 and y = 25, then (x+y)^{\frac{1}{2}} =
6
-6
\frac{\sqrt{11}}{55}
\frac{1}{6}
-\frac{1}{6}
Factor 16x^4 - 1
(2x-1)^2(2x+1)^2
(4x-1)^2(4x+1)^2
(2x-1)(2x+1)(4x^2+1)
(2x-1)(2x+1)(2x^2-1)
(2x-1)(2x+1)(2x^2+1)