Copy of Theoretical Yield, Percent Yield, Limiting Reagent Ques 1 (5/28/2026)

Last updated about 1 month ago

4 Nsɛmmisa

The following reaction was performed:

FeBr₂ + KCl → FeCl₂ + KBr

34 grams of iron bromide is reacted with an excess of potassium chloride to form 4.0 g of iron chloride.

Step 1 - Balance the equation (put a 1 in the blank if there is no coefficient).

FeBr₂ + KCl → FeCl₂ + KBr

Step 2 - Calculate the theoretical yield of FeCl₂

Theoretical Yield of FeCl₂ g - round to the nearest whole number.

Step 3 - Percent yield of FeCl₂ - round to the nearest whole number.

Percent yield %

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The following reaction was performed:

TiS + H₂O → H₂S + TiO

20 grams of titanium sulfide is reacted with an excess of dihydrogen monoxide to form 14.9 grams of titanium oxide.

Step 1 - Balance the equation (put a 1 in the blank if there is no coefficient).

TiS + H₂O → H₂S + TiO

Step 2 - Calculate the theoretical yield of TiO

Theoretical Yield TiO g - round to the nearest tenth.

Step 3 - Percent yield of TiO.

Percent yield % - round to the nearest tenth.

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Copy of Theoretical Yield, Percent Yield, Limiting Reagent Ques 1 (5/28/2026)

Last updated about 1 month ago

4 Nsɛmmisa

The following reaction was performed:

FeBr₂ + KCl → FeCl₂ + KBr

34 grams of iron bromide is reacted with an excess of potassium chloride to form 4.0 g of iron chloride.

Step 1 - Balance the equation (put a 1 in the blank if there is no coefficient).

FeBr₂ + KCl → FeCl₂ + KBr

Step 2 - Calculate the theoretical yield of FeCl₂

Theoretical Yield of FeCl₂ g - round to the nearest whole number.

Step 3 - Percent yield of FeCl₂ - round to the nearest whole number.

Percent yield %

null

The following reaction was performed:

TiS + H₂O → H₂S + TiO

20 grams of titanium sulfide is reacted with an excess of dihydrogen monoxide to form 14.9 grams of titanium oxide.

Step 1 - Balance the equation (put a 1 in the blank if there is no coefficient).

TiS + H₂O → H₂S + TiO

Step 2 - Calculate the theoretical yield of TiO

Theoretical Yield TiO g - round to the nearest tenth.

Step 3 - Percent yield of TiO.

Percent yield % - round to the nearest tenth.

null

The following reaction was performed:

H₂SO₄ → H₂O + SO₃

89.0 g sulfuric acid decomposes to form 7.1 g dihydrogen monoxide.

Step 1 - Balance the equation (put a 1 in the blank if there is no coefficient).

H₂SO₄ → H₂O + SO₃

Step 2 - Calculate the theoretical yield of H₂O

Theoretical Yield g - round to the nearest tenth.

Step 3 - Percent yield of H₂O.

Percent yield % - round to the nearest tenth.

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The following reaction was performed:

Pb(NO₃)₂ + NaI → PbI₂ + NaNO₃

25.2 grams of lead nitrate is reacted with 15.5 grams of sodium iodide to form 6.2 grams of sodium nitrate.

Step 1 - Balance the equation (put a 1 in the blank if there is no coefficient).

Pb(NO₃)₂+ NaI → PbI₂ + NaNO₃

Step 2 - Calculate the theoretical yield of NaNO₃

For Pb(NO₃)₂ → Theoretical Yield NaNO₃ g - round to the nearest tenth.
For NaI → Theoretical Yield NaNO₃ g - round to the nearest tenth.

Step 3 - Identifying the Limiting Reagent (which reactant had the lowest TY?)

Limiting Reagent =

Step 4 - Percent yield of NaNO₃(calculate the % yield of the LR)

Percent yield % - round to the nearest tenth.

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